How to fetch feed url from web page in python

Easyly.

import urllib2
from lxml import etree

webPageUrl = "http://www.osmonov.com"
try:
    opener = urllib2.build_opener()
    response = opener.open(webPageUrl)
    if response.headers.__getitem__('Content-Type').startswith('text/html'):
        html_element = etree.HTML( response.read() )
        link_elements =html_element.findall('.//link[@rel="alternate"]')
        if link_elements.__len__() > 0:
            # so we can have several link tags, i use just the first
            feedUrl = link_elements.__getitem__(0).get('href')

except urllib2.URLError:
    # commander! do something violent

hi.kg API

Dear Sudar'! ^_^
Please! Try out hi.kg API.
It's implemented on json-rpc.
url: http://hi.kg/api.php
method: shorten
argument: url
return: shorten_url

Some examples:

<?php

require_once("jsonRPCClient.php");
$client = new jsonRPCClient("http://hi.kg/api.php");

echo $client->shorten( "http://www.osmonov.com");

?>

Also JSON-RPC PHP lib here

Have a nice shortening!